The average atomic mass of nitrogen is 14.0067. The atomic masses of the two stable isotopes of nitrogen.^14 N and^15 N, are 14.003074002 and 15.00010897 amu, respectively. Use this information to determine the percent abundance of^14 N. % Determine the percent abundance of^15 N. %

The answer to your question is Abundance N-14 = 99.63%

                                                    Abundance N-15 = 0.37%

Explanation:

Data

Average atomic mass = 14.0067 amu

N-14 = 14.003074002

N-15 = 15.00010897

Abundance N-14 = ?   x

Abundance N-15 = ?   1 - x

Formula

Average atomic mass = (mass of N-14)x + (mass of N-15)(1 - x)

Substitution

14.0067 = 14.003074002x + 15.00010897(1 - x)

Solve for x

14.0067 = 14.003074002x + 15.00010897 - 15.00010897x

14.0067 - 15.00010897 = 14.003074002x - 15.00010897x

-0.9934 = -0.99703x

x = -0.9934 / -0.99703

x = 0.9963

Conclusion

Abundance N-14 = 0.9963 x 100 = 99.63 %

Abundance N-15 = 1 - 0.9963 = 0.0037 x 100 = 0.37 %

C. the turtle’s movements are awkward and difficult.

Explanation:

The verb to drag means pulling forcefully with difficulty. As a result, the turtle struggles to move because of her hard protective shell, which has thick bony plates on it, so the it moves slowly in not very deep waters and through the water plants.