rockstargirl9869
08.12.2020 •
Chemistry
The binding energy of electrons in a metal is 193 kJ/mol. Determine the threshold frequency for this metal.
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Ответ:
need points
Explanation:
Ответ:
They frequency = 3.9 * 10^16 Hz
The amount of energy E = 2.58 *10^-17 J
Explanation:
Step 1: Data given
wavelength is 7.67 * 10^-7 cm
Step 2: Calculate the frequency
f = c / λ
⇒ with λ = the wavelength in nm = 7.67 nm
⇒ with c = the speed of light = 3.00 * 10^8 m/s
⇒ f = the frequency = TO BE DETERMINED
f = (3.00 * 10^8 m/s) / 7.67 * 10^-9 m
f = 3.9 * 10 ^16 /s = 3.9 * 10^16 Hz
They frequency is 3.9 * 10^16 Hz
Step 3: Calculate the amount of energy
E = h *f
⇒ with E = the amount of energy (in joule)
⇒ h = Planck's constant = 6.626 *10^-34 J*s
⇒ with f = the frequency
E = 6.626 *10^-34 J*s * 3.9 * 10^16 Hz
E = 2.58 *10^-17 J