brillamontijo
28.01.2020 •
Chemistry
The brackets used to express concentration [ ], when making equilibrium constant calculations,
grams per liter
ounces per liter
moles per liter
pounds per liter
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Ответ:
Ответ:
Structures Attached
Explanation:
1.Total Number of e⁻ in NF₃
Number of e in Nitrogen = 5
Number of e in Flourine = 7
Total Number of e⁻ in NF₃ = 5 + 7(3)
Total Number of e⁻ in NF₃ = 5 + 21
Total Number of e⁻ in NF₃ = 26
2.Total Number of e⁻ in H₂S
Number of e in Hydrogen = 1
Number of e in sulphur = 6
Total Number of e⁻ in H₂S = 1(2) + 6
Total Number of e⁻ in H₂S = 2 + 6
Total Number of e⁻ in H₂S = 8
3.Total Number of e⁻ in F₂
Number of e in Flourine = 7
Total Number of e⁻ in F₂ = 7(2)
Total Number of e⁻ in F₂ = 14
4.Total Number of e⁻ in CO
Number of e in carbon = 4
Number of e in oxygen = 6
Total Number of e⁻ in CO = 4 + 6
Total Number of e⁻ in CO = 10
5.Total Number of e⁻ in SO₂
Number of e in Sulphur = 6
Number of e in oxygen = 6
Total Number of e⁻ in SO₂ = 6 + 6(2)
Total Number of e⁻ in SO₂ = 6 + 12
Total Number of e⁻ in SO₂ = 18
6.Total Number of e⁻ in O₂
Number of e in Oxygen = 6
Total Number of e⁻ in O₂ = 6(2)
Total Number of e⁻ in O₂ = 12
7.Total Number of e⁻ in SF₂
Number of e in Sulphur = 6
Number of e in Flourine = 7
Total Number of e⁻ in SF₂ = 6 + 7(2)
Total Number of e⁻ in SF₂ = 6 + 14
Total Number of e⁻ in SF₂ = 20
8.Total Number of e⁻ in BH₃
Number of e in Boron = 3
Number of e in Hydrogen = 1
Total Number of e⁻ in BH₃ = 3 + 1(3)
Total Number of e⁻ in BH₃ = 3 + 3
Total Number of e⁻ in BH₃ = 6
9.Total Number of e⁻ in CHCl₃
Number of e in Carbon = 4
Number of e in Hydrogen = 1
Number of e in chlorine = 7
Total Number of e⁻ in CHCl₃ = 4 + 1+ 7(3)
Total Number of e⁻ in CHCl₃ = 4 + 1 + 21
Total Number of e⁻ in CHCl₃ = 26
10.Total Number of e⁻ in CS₂
Number of e in Carbon = 4
Number of e in Sulphur = 6
Total Number of e⁻ in CS₂ = 4 + 6(2)
Total Number of e⁻ in CS₂ = 4 + 12
Total Number of e⁻ in CS₂ = 16
11.Total Number of e⁻ in BeCl₂
Number of e in Beryllium = 2
Number of e in Chlorine = 7
Total Number of e⁻ in BeCl₂ = 2 + 7(2)
Total Number of e⁻ in BeCl₂ = 2 + 14
Total Number of e⁻ in BeCl₂ = 16
12.Total Number of e⁻ in HCN
Number of e⁻ in Hydrogen = 1
Number of e⁻ in Carbon = 4
Number of e⁻ in Nitrogen = 5
Total Number of e⁻ in HCN = 1 + 4 + 5
Total Number of e⁻ in HCN = 10
13.Total Number of e⁻ in C₂H₂
Number of e⁻ in Carbon = 4
Number of e⁻ in Hydrogen = 1
Total Number of e⁻ in C₂H₂ = 4(2) + 1(2)
Total Number of e⁻ in C₂H₂ = 8 + 2
Total Number of e⁻ in C₂H₂ = 10
14.Total Number of e⁻ in SiO₂
Number of e⁻ in Silicon = 4
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in SiO₂ = 4 + 6(2)
Total Number of e⁻ in SiO₂ = 4 + 12
Total Number of e⁻ in SiO₂ = 16
15.Total Number of e⁻ in H₂O₂
Number of e⁻ in Hydrogen = 1
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in H₂O₂ = 1(2) + 6(2)
Total Number of e⁻ in H₂O₂ = 2 + 12
Total Number of e⁻ in H₂O₂ = 14
16.Total Number of e⁻ in SO₂⁻
Number of e in Sulphur = 6
Number of e in Oxygen = 6
Total Number of e⁻ in SO₂⁻ = 6 + 6(2)
Total Number of e⁻ in SO₂⁻ = 6 + 12
Total Number of e⁻ in SO₂⁻ = 18
17.Total Number of e⁻ in CH₃OH
Number of e⁻ in Carbon = 4
Number of e⁻ in Hydrogen = 1
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in CH₃OH = 4 + 1(3) + 6 + 1
Total Number of e⁻ in CH₃OH = 4 + 3 + 6 + 1
Total Number of e⁻ in CH₃OH = 14
18.Total Number of e⁻ in NO₃
Number of e⁻ in Nitrogen = 5
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in NO₃ = 5 + 6(3)
Total Number of e⁻ in NO₃ = 5 + 18
Total Number of e⁻ in NO₃ = 23
19.Total Number of e⁻ in ClO
Number of e⁻ in Chlorine = 7
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in ClO = 7 + 6
Total Number of e⁻ in ClO = 7 + 6
Total Number of e⁻ in ClO = 13
20.Total Number of e⁻ in CH₂O
Number of e⁻ in Carbon = 4
Number of e⁻ in Hydrogen = 1
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in CH₂O = 4 + 1(2) + 6
Total Number of e⁻ in CH₂O = 4 + 2 + 6
Total Number of e⁻ in CH₂O = 12