The combustion of propane occurs when propane interacts with oxygen gas to produce water and carbon dioxide in the following reaction:
c3h8 (g) + 5o2 (g) → 3co2 (g) + 4h2o(l)
if 2 moles of propane c3h8 (g) react at 373 k in a volume of 2.5 l, what is the pressure in the cylinder from the c3h8 (g)?
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Ответ:
Explanation:
1) Data:
a) n = 2 moles
b) T = 373 K
c) V = 2.5 liter
d) P = ?
2) Chemical principles and formula
You need to calculate the pressure of the propane gas in the mixture before reacting. So, you can apply the partial pressure principle which states that each gas exerts a pressure as if it occupies the entire volume.
Thus, you just have to use the ideal gas equation: PV = nRT
3) Solution:
PV = nRT ⇒ P = nRT / VP = 2 mol × 0.08206 atm-liter /K-mol × 373K / 2.5 liter = 24.5 atm
Since the number of moles are reported with one significant figure, you must round your answer to one significant figure, and that is 20 atm (20 is closer to 24.5 than to 30).
Ответ:
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question we have
We have the final answer as
5 cm³Hope this helps you