The decomposition of potassium chlorate into kcl & o2 is used as a source of oxygen in the laboratory. how many moles of potassium chlorate are needed to produce 15 mol of oxygen gas?
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Ответ:
10moles of kcl
Explanation:
2 K C l O3 → 2 K C l + 3 O 2
Notice that you have a 2 : 3 mole ratio between potassium chlorate and oxygen gas, which means that, regardless of how many moles of the former react, you'll always produce 2/3 times more moles of the latter.
15 mol of O2 * ((2mol of KCLO3)/(3mol of O2))= 15*2/3=10 Mol
Ответ:
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