The electron pair in a C-F bond could be considered Question 3 options: closer to C because carbon has a larger radius and thus exerts greater control over the shared electron pair closer to C because carbon has a lower electronegativity than fluorine an inadequate model since the bond is ionic centrally located directly between the C and F closer to F because fluorine has a higher electronegativity than carbon

closer to F because fluorine has a higher electronegativity than carbon

Explanation:

Electronegativity refers to the ability of an atom in a bonding situation to draw the shared electrons of the bond closer to itself.

Electronegativity increases across the period and decreases down the group. A highly electronegative atom draws the shared electron pair of a bond towards itself.

When two atoms are bonded together, the electron pair is always drawn closer to the atom that has a higher electronegativity.

Hence, the electron pair in a C-F bond could be considered closer to F because fluorine has a higher electronegativity than carbon.

2.67 x 10⁷km

Explanation:

Given parameters:

    Time of arrival of p-waves  = 2: 10: 00

    Time of arrival of s-waves = 2: 15: 20

Unknown:

Distance of wave from epicenter  = ?

Solution:

 To find the distance of the wave from the epicenter;

     Distance = 3 x 10⁸ x time interval

Time interval = Time of arrival of p-waves  - Time of arrival of s-waves

                       =  2: 10: 00 - 2: 15: 20

                       = 5min 20s

                       = 320s

Now, we need to convert the time to hrs;

        3600s  = 1hr

         320s  =  = hr

So,

   Distance =  3 x 10⁸  x   = 2.67 x 10⁷km