The equilibrium constant, kc, for the following reaction is 5.10×10-6 at 548 k. nh4cl(s) nh3(g) + hcl(g) calculate the equilibrium concentration of hcl when 0.564 moles of nh4cl(s) are introduced into a 1.00 l vessel at 548 k.[hcl] = m

The equilibrium concentration of HCl is

Explanation:

We are given:

Moles of = 0.564 moles

Volume of vessel = 1.00 L

Molarity is calculated by using the equation:

Molarity of

The given chemical equation follows:

                 

Initial:         0.564

At eqllm:     0.564-x          x              x

The expression of for above equation follows:

The concentration of pure solid and pure liquid is taken as 1.

We are given:

Putting values in above equation, we get:

Negative sign is neglected because concentration cannot be negative.

So,

Hence, the equilibrium concentration of HCl is

An atoms atomic mass is the sum of it's proton and neutrons found in the nucleus. An atom's atomic number is the number of protons an atom has. By subtracting an element's atomic number from the atomic mass you can calculate the number of neutrons. For oxygen it would be sixteen minus eight, so oxygen has eight neutrons.