A211 g sample of barium carbonate, baco3, reacts with a solution of nitric acid to give barium nitrate, carbon dioxide, and water. if the acid is present in excess, what mass and volume of dry carbon dioxide gas at stp will be produced?
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Ответ:
Volume = 23.94 L
Solution:
The equation for given reaction is as follow,
BaCO₃ + 2 HNO₃ → Ba(NO₃)₂ + CO₂ + H₂O
According to this equation,
197.34 g (1 mole) BaCO₃ produces = 44 g (1 mole) of CO₂
So,
211 g of BaCO₃ will produce = X g of CO₂
Solving for X,
X = (211 g × 44 g) ÷ 197.34 g
X = 47.04 g of CO₂
As we know,
44 g (1 mole) CO₂ at STP occupies = 22.4 L volume
So,
47.04 g of CO₂ will occupy = X L of Volume
Solving for X,
X = (47.04 g × 22.4 L) ÷ 44 g
X = 23.94 L Volume
Ответ: