Chemistry: The fizz produced when an alka-seltzer tablet is dissolved in water is due to the reaction between sodium bicarbonate (nahco₃) and citric acid (h₃c₆h₅o₇): 3nahco₃(aq) + h₃c₆h₅o₇(aq) 3co₂(g) + 3h₂o(l) + na₃c₆h₅o₇(aq) in a certain experiment 1.00g of sodium bicarbonate and 1.00g of citric acid are allowed to react. how many grams of carbon dioxide form?

The answer to your question isC. Atoms are always in motion....

The fizz produced when an alka-seltzer tablet

kennedy6010

08.01.2022

0.47g of $CO_{2}$

Explanation:

1. Balanced equation:

3NaHCO₃(aq) + H₃C₆H₅O₇(aq) --------> 3CO₂(g) + 3H₂O(l) + Na₃C₆H₅O₇(aq)

2. Find the limiting reagent between the reactants:

-For the $NaHCO_{3}$ :

$1gNaHCO_{3}*\frac{1molNaHCO_{3}}{84gNaHCO_{3}}=0.012molesNaHCO_{3}$

Divide the number of moles between the stoichiometric coefficient of the $NaHCO_{3}$ :

$\frac{0.012}{3}=0.004$

-For the $H_{3}C_{6}H_{5}O_{7}$ :

$1gH_{3}C_{6}H_{5}O_{7}*\frac{1molH_{3}C_{6}H_{5}O_{7}}{192gH_{3}C_{6}H_{5}O_{7}}=0.005molesH_{3}C_{6}H_{5}O_{7}$

Divide the number of moles between the stoichiometric coefficient of the $H_{3}C_{6}H_{5}O_{7}$ :

$\frac{0.005}{1}=0.005$

The smallest number is the 0.004 therefore, the limiting reagent is the sodium bicarbonate.

3. Calculate the grams of carbon dioxide:

$1gNaHCO_{3}*\frac{1molNaHCO_{3}}{94gNaHCO_{3}}*\frac{3molesCO_{2}}{3molesNaHCO_{3}}*\frac{44gCO_{2}}{1molCO_{2}}=0.47gCO_{2}$

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