The following observations are made about two hypothetical elements A and B: The A?A and B?Bbond lengths in elemental A and B are 2.65 and 1.84 Å, respectively. A and B react to form the binary compound AB2, which has a linear structure (that is ?B?A?B=180? ).

Based on these statements, predict the separation between the two B nuclei in a molecule of AB2

Explanation:

The concept of bond length is applied here. Bond length is the distance between the nuclei of atoms in molecules. it can be measured in different ways by X-ray diffraction. It should be noted that the shorter the bond length, the stronger the bond.

Given Bond length of A-A = 2ra, where ra = atomic radius of A2ra = 2.65 Åsimilarly, bond length of B-B = 2rb = 1.84 Å, where rb = atomic radius of BIn AB2, separation between the two nuclei of B = rb + 2ra + rb= 2rb + 2ra = 1.84 Å + 2.65 Å = 4.49Å

C. 4x10⁻⁴ mol / (Ls)

Explanation:

Based in the reaction:

5 H₂O₂(aq) + 2 MnO₄⁻(aq) + 6 H⁺(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 O₂(g)

2 moles of MnO₄⁻ disappears while 5 moles of O₂ appears.

If 5 moles appears in a rate of 1.0x10⁻³mol /(Ls), 2 moles will disappear:

2 moles ₓ (1.0x10⁻³mol /(Ls) / 5 moles) = 4x10⁻⁴ mol / (Ls)

Right answer is:

C. 4x10⁻⁴ mol / (Ls)