The half-life of the radioactive element unobtanium dash 53 is 20 seconds. if 32 grams of unobtanium dash 53 are initially present, how many grams are present after 20 seconds? 40 seconds? 60 seconds? 80 seconds? 100 seconds?
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Ответ:
The half-life of a radioactive element is defined as the time required by the specific isotope to decrease by half of its original value. The unobtanium after given time will be present as:
After 20 secs, 16 gramsAfter 40 secs, 8 gramsAfter 60 secs, 4 gramsAfter 80 secs, 2 gramsAfter 100 secs, 1 gramHalf-life is the time required by the unobtanium is the half of the reaction is completed. Half of the substance will be decomposed, such that:
Amount of substance left n half-lives =
where A= initial amount of substance
Now,
n = number of half-lives = given time /half-life
Given,
1. Time = t = 20 seconds
Number of half-lives =2.Time = t = 40 seconds
Number of half-lives =3.Time = t = 60 seconds
Number of half-lives =4.Time = t = 80 seconds
Number of half-lives =5.Time = t = 100 seconds
Number of half-lives =To know more about half-life, refer to the following link:
link
Ответ:
After 20 seconds, 16 grams of unobtanium will be present, after 40 seconds, 8 grams of unobtanium will be present after 60 seconds, 4 grams of unobtanium will be present, after 80 seconds, 2 grams of unobtanium will be present and after 100 seconds, 1 grams of unobtanium will be present.
Explanation: Half life is the time in which half of the reaction is completed. Thus the half of the substance will be decomposed and half of it will remain.
Amount of the substance left after n half lives will be=![\frac{A}{2^n}](/tpl/images/0118/0431/1cf0b.png)
where A= initial amount of substance
n=no of half lives=![\frac{\text{given time}}{\text{half life}}](/tpl/images/0118/0431/498d2.png)
a) t= 20 seconds
no of half lives=![\frac{20}{20}=1](/tpl/images/0118/0431/7c440.png)
amount of the substance left after 1 half life will be=
=16 g.
b) t= 40 seconds
no of half lives=![\frac{40}{20}=2](/tpl/images/0118/0431/486df.png)
amount of the substance left after 2 half lives will be=
=8g.
c) t= 60 seconds
no of half lives=![\frac{60}{20}=3](/tpl/images/0118/0431/27053.png)
amount of the substance left after 3 half lives will be=![\frac{32}{2^3}=4g](/tpl/images/0118/0431/4d0a7.png)
d) t= 80 seconds
no of half lives=![\frac{80}{20}=4](/tpl/images/0118/0431/27eb3.png)
amount of the substance left after 4 half lives will be=![\frac{32}{2^4}=2g](/tpl/images/0118/0431/ff696.png)
e) t= 100 seconds
no of half lives=![\frac{100}{20}=5](/tpl/images/0118/0431/989b9.png)
amount of the substance left after 5 half lives will be=![\frac{32}{2^5}=1g.](/tpl/images/0118/0431/94be1.png)
Ответ:
is there more information please