Chemistry: The net ionic equation for the dissolution of zinc metal in aqueous hydrobromic acid is the net ionic equation for the dissolution of zinc metal in aqueous hydrobromic acid is zn (s) + 2h+ (aq) → zn2+ (aq) + h2 (g) 2zn (s) + h+ (aq) → 2zn2+ (aq) + h2 (g) zn (s) + 2hbr (aq) → znbr2 (aq) + 2h+ (aq) zn (s) + 2br- (aq) → znbr2 (aq) zn (s) + 2hbr (aq) → znbr2 (s) + 2h+ (aq)

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The net ionic equation for the dissolution of zinc

jforeman42

10.03.2022

Answer : The correct net ionic equation will be,

$Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)$

Explanation :

Spectator ions : It is defined as the same number of ions present on reactant and product side that do not participate in the reactions.

In the net ionic equations, we are not include the spectator ions in the equations.

The given balanced ionic equation will be,

$Zn(s)+2HBr(aq)\rightarrow ZnBr_2(aq)+H_2(g)$

The ionic equation in separated aqueous solution will be,

$Zn(s)+2H^+(aq)+2Br^-(aq)\rightarrow Zn^{2+}(aq)+2Br^-(aq)+H_2(g)$

In this equation, Br^- ion is the spectator ions.

By removing the Br^- , spectator ions from the balanced ionic equation, we get the net ionic equation.

Hence, the net ionic equation will be,

$Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)$

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