jasminejohnson4330
24.02.2022 •
Chemistry
The normal boiling point of ethanol is 78.3C. At this temperature, the vapour pressure of an ethanolic solution is 96 kpa. Calculate the mole fraction of the solute
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Ответ:
a) 1592.4 kg C8H10
b) 15*10³ mol C8H10
c) 33.1 lb-mole
d) 1.2 *10^5 mol C
e) 1.5 * 10^5 mol H
f) 1.44 * 10^6 grams C
g) 1.52 * 10^5 grams H
h) 9.03*10^27 molecules C8H10
Explanation:
Step 1: Data given
Number of moles C8H10 = 15.0 kmol =15000 moles
Molar mass of C8H10 = 106.16 g/mol
Step 2: Calculate mass C8H10
Mass C8H10 = moles C8H10 * molar mass C8H10
Mass C8H10 = 15000 * 106.16 g/mol
Mass C8H10 = 1592400 grams = 1592.4 kg
Step 3: Calculate moles C8H10
15.0 kmol = 15*10³ mol C8H10
Step 4: Calculate lb-mol
15.0 kmol = 33.1 lb-mole
Step 5: Calculate moles of C
For 1 mol C8H10 we have 8 moles of C
For 15*10³ mol C8H10 we have 8* 15*10³ =1.2 *10^5 mol C
Step 6: Calculate moles H
For 1 mol C8H10 we have 10 moles of H
For 15*10³ mol C8H10 we have 10* 15*10³ = 1.5 * 10^5 mol H
Step 7: Calculate mass of C
Mass C = moles C * molar mass C
Mass C = 1.2 *10^5 mol C * 12 g/mol
Mass C = 1.44 * 10^6 grams
Step 8: Calculate mass of H
Mass H = moles H * molar mass H
Mass H = 1.5 *10^5 mol H * 1.01 g/mol
Mass C = 1.52 * 10^5 grams
Step 9: Calculate molecules of C8H10
Number of molecules = number of moles * number of Avogadro
Number of molecules = 15*10³ mol C8H10 * 6.022*10^23
Number of molecules = 9.03*10^27 molecules