The osmotic pressure of a solution containing 22.7 mg of an unknown protein in 50.0 mL of solution is 2.88 mmHg at 25 C. Determine the molar mass of the protein.
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Ответ:
Molar mass for the protein is 2929.03 g/mol
Explanation:
To determine the osmotic pressure (one of the four colligative properties) we apply this formula:
π = M . R . T
π → Pressure
It must be in atm, so let's convert the mmHg to atm
2.88 mmHg . 1 atm / 760 mmHg = 0.00378 atm
T → Absolute T° (K) = T°C + 273 → 25°C + 273 = 298K
R = 0.082 L.atm/mol.K
Let's replace data: 0.00378 atm = M . 0.082 L.atm/mol.K . 298K
0.00378 atm / (0.082 L.atm/mol.K . 298K) = M
1.55×10⁻⁴ mol/L = M
These are the moles of protein that are contained in 1L of solution, but our volume is 50mL. Let's convert it to L
50mL . 1L / 1000 mL = 0.05 L
Now we can determine the moles of protein we used
1.55×10⁻⁴ mol/L . 0.05L = 7.75×10⁻⁶ moles
This moles corresponds to 22.7 mg of mass. Let's convert the mg to g to find out the molar mas mass
22.7 mg . 1g / 1000 mg = 0.0227 g
Molar mass → g/mol → 0.0227 g / 7.75×10⁻⁶ moles = 2929.03 g/mol
Ответ:
Alpha particles carry a positive charge, beta particles carry a negative charge, and gamma rays are neutral. An alpha particle is made up of two protons and two neutrons bound together. Beta particles are high energy electrons. Gamma rays are waves of electromagnetic energy, or photons.