The p K a of hypochlorous acid is 7.530 . A 60.0 mL solution of 0.103 M sodium hypochlorite ( NaOCl ) is titrated with 0.296 M HCl . Calculate the pH of the solution after the addition of 8.00 mL of 0.296 M HCl .
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Ответ:
pH of the solution after addition of 8 ml 0,296 molar HCl = 7.94
Explanation:
In this case buffer exist between hypochlorous acid HClO is a weak acid and its conjugate base hypochlorite ion ClO⁻ which are deliver to the solution by NaOCl ( sodium hypochlorite ).
The salt is completely dissociate
[NaOCl] = [ClO⁻]
Using Henderson equation to find pH of this buffer
pH = pKa + log![\frac{[Conjugate base]}{[Acid]}](/tpl/images/0559/7901/225c1.png)
or, = 7.53 + log![\frac{60 X 0.103}{8 X 0.296}](/tpl/images/0559/7901/d5d02.png)
or, = 7.53 + 0.4
or, = 7.94
Ответ:
the formula for heat capacity is q=mct but the formula for specific heat is c= q/mt so to caluclate the specific heat of a metal, you use c=q/mt