The partial pressures of CH4, N2, and O2 in a sample of gas were found to be 143 mmHg, 469 mmHg, and 563 mmHg, respectively. Calculate the mole fraction of oxygen. 20.1 0.399 0.741 0.479 0.359

The mole fraction of oxygen gas is 0.479

Explanation:

We are given:

Partial pressure of methane = 143 mmHg

Partial pressure of nitrogen gas = 469 mmHg

Partial pressure of oxygen gas = 563 mmHg

Total pressure = (143 + 469 + 563) = 1175 mmHg

To calculate the mole fraction of oxygen gas, we use the equation given by Raoult's law, which is:

where,

= partial pressure of oxygen gas = 563 mmHg

= total pressure = 1175 mmHg

= mole fraction of oxygen gas = ?

Putting values in above equation, we get:

Hence, the mole fraction of oxygen gas is 0.479

a liter is larger, hope that helps :)