Chemistry: The pH of an acid solution is 5.82. Calculate the Ka for the monoprotic acid. The initial acid concentration is 0.010 M.

The pH of an acid solution is 5.82. Calculate the

Ответ:

peytonamandac9114

31.01.2022

Chemistry

The answer is

$Ka = 2.29 \times {10}^{ - 14} moldm^{ - 3}$

Explanation:

The Ka of an acid when given the pH and concentration can be found by

$pH = - \frac{1}{2} log(Ka) - \frac{1}{2} log(c)$

where

c is the concentration of the acid

From the question

pH = 5.82

c = 0.010 M

Substitute the values into the above formula and solve for Ka

We have

$5.82 = - \frac{1}{2} log(Ka) - \frac{1}{2} log(0.010)$ $- \frac{1}{2} log(Ka) = 5.82 + 1$ $- \frac{1}{2} log(Ka) = 6.82$

Multiply through by - 2

Find antilog of both sides

We have the final answer as

$Ka = 2.29 \times {10}^{ - 14} moldm^{ - 3}$

Hope this helps you

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Ответ:

kaziyahf2006

23.12.2022

Chemistry

Answer

The endothermic process is a term that describes a reaction where the system absorbs the energy from its surrounding in the form of heat. A few examples of the endothermic process are photosynthesis, evaporating liquids, melting ice, dry ice, alkanes cracking, thermal decomposition, ammonium chloride in water and much more.

The exothermic reaction is the opposite of an endothermic reaction. It releases energy by light or heat to its surrounding. A few examples are neutralization, burning a substance, reactions of fuels, deposition of dry ice, respiration, solution of sulfuric acid into water and much more.

Explanation:

Endo example= ice cream

Exo example= Hot coffee

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The pH of an acid solution is 5.82. Calculate the Ka for the monoprotic acid. The initial acid concentration is 0.010 M.

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