The pressure of a 5.2mol sample of C3H8 in a 35.3 L container is measured to be 5.5 atm. What is the temperature of this gas in kelvins?

T° = 453.6 K

Explanation:

Let's apply the Ideal Gases Law to solve the question:

Pressure . Volume = number of moles . R . T°

We replace data:

5.5 atm . 35.3L = 5.2 mol . 0.082 L.atm/mol.K .T°

T° = (5.5 atm . 35.3L) / (5.2 mol . 0.082 L.atm/mol.K)

T° = 453.6 K

The Ideal Gases Law contains the Absolute value of T° (Kelvin degrees)

So the final answer is: 453.6 K

You can also determine this, because the unit of R (Ideal Gases constant)

532.2546

Explanation:

if i ask how many grams Are in a mole of N2 it would be 28.0134 grams and your asking 19 so 28.0134 x 19 would be 532.2546 grams