The purification of hydrogen gas is accomplished by diffusion through a palladium sheet. compute the number of kilograms of hydrogen that pass per hour through a 6-mm thick sheet of palladium having an area of 0.25 m2 at 600°c. assume a diffusion coefficient of 1.7 × 10–8 m2/s that the respective concentrations at the high- and low-pressure sides of the plate are 2.0 and 0.4 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained. express your answer in engineering format in kg/hour to two significant figure

= 4.08 × 10^-3 kg/h

This problem calls for the mass of hydrogen, per hour, that diffuses through a Pd sheet.

M = JAt = -DAt (ΔC/Δx)

   Where D = 1.7 × 10^–8 m2/s, A is area; 0.25 m², t =3600s/h

ΔC =( 0.4 - 2.0) kg/m³, Δx = 6 mm or 6 × 10^-3 m

Therefore;

    = -(1.7 × 10^–8 m2/s)(0.25 m²)(3600 s/h) [(0.4 - 2.0) kg/m³)/6 × 10^-3]

    = 4.08 × 10^-3 kg/h

Explanation:

Short Yes.

The coefficients may not be conserved, but mass always has to be. Take this equation as an example

2 Mg3P2 ===>   6Mg + P4

There is a 2 on the left side and 6 and 1 on the right. I hope you mean that the coefficient 2 is not equal to 7.

But let's look a little closer. You have to look at the molecular structure of the left and right side.

2Mg3P2 has 6 Mgs and 4 Ps on the left side.

6Mg is on the right. They are free standing.

P4    has 1 molecule consisting of 4 Ps.

Everything balances.

This is a terrific question to be asking. You need to understand the internal balance numbers vs the molecular ones on the out side.

That sounds like a bit of gobbledygook and it takes a bit of study.

2 Mg3P2 means that Mg3P2 is written twice.

Mg3P2 ==> "3 Mg2+   +  2P3+   and there is another one written the same way.

Mg3P2 ==> "3 Mg2+   +  2P3+