![musicismylove2340](/avatars/13302.jpg)
musicismylove2340
30.06.2021 •
Chemistry
cetic acid (HC2H3O2) is an important component of vinegar. A 10.00-mL sample of vinegar is titrated with 0.5052 M NaOH, and 16.88 mL are required to neutralize the acetic acid that is present. Write a balanced equation for this neutralization reaction. What is the molarity of the acetic acid in this vinegar
Solved
Show answers
More tips
- H Health and Medicine How to Choose the Right Tanning Cream?...
- C Computers and Internet How to Download Movies from Torrents?...
- S Style and Beauty How to Sew Harem Pants?...
- C Computers and Internet Е-head: How it Simplifies Life for Users?...
- F Family and Home How to Choose the Best Diapers for Your Baby?...
- F Family and Home Parquet or laminate, which is better?...
- L Leisure and Entertainment How to Properly Wind Fishing Line onto a Reel?...
- L Leisure and Entertainment How to Make a Paper Boat in Simple Steps...
- T Travel and tourism Maldives Adventures: What is the Best Season to Visit the Luxurious Beaches?...
- H Health and Medicine Kinesiology: What is it and How Does it Work?...
Answers on questions: Chemistry
- M Mathematics If -6a = -48, then a =...
- M Mathematics The graph shows the number of visits your website received over the past 6 months. Interpret each plotted point in the graph. Then identify the unit rate. Graph titled, Website...
- P Physics Acounty commissioner wants to reduce the amount of waste sent to the local landfill. which of the following would result in the greatest reduction of waste....
Ответ:
The molarity of the acetic acid in this vinegar is 0.853 M
Explanation:
Step 1: Data given
Volume of vinegar sample = 10.00 mL
Concentration of NaOH = 0.5052 M
16.88 mL are required to neutralize the acetic acid
Step 2: The reaction
HC2H3O2(aq) + NaOH(aq) ⇔ NaC2H3O2(aq) + H2O(l)
Step 3: Calculate molarity of cetic acid (HC2H3O2)
C1*V1 = C2*V2
⇒with C1 = the molarity ofHC2H3O2= TO BE DETERMINED
⇒with V1 = the volume of HC2H3O2 = 10.00 mL = 0.01 L
⇒with C2 = the molarity of NaOH = 0.5052 M
⇒with V2 = the volume of NaOH = 16.88 mL = 0.01688L
C1 = (C2*V2)V1
C1 = (0.5052 * 0.01688 ) / 0.01
C1 = 0.853 M
The molarity of the acetic acid in this vinegar is 0.853 M
Ответ:
Search Results
Featured snippet from the web
To calculate the numbers of subatomic particles in an atom, use its atomic number and mass number:
number of protons = atomic number.
number of electrons = atomic number.
number of neutrons = mass number - atomic number.
Explanation: