Chemistry: The pyrolysis of ethane proceeds with an activation energy of about 300 kj/mol. how much faster is the decomposition at 625°c than at 525°c?

The pyrolysis of ethane proceeds with an activation

isabellecannuli

04.01.2022

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

K_2 = rate of reaction at T_2

K_1 = rate of reaction at T_1

= activation energy of the reaction

R = gas constant = 8.314 J/K mol

E_a=300 kJ/mol=300,000 J/mol

T_2=625^oC=898.15 K,T_1=525^oC=798.15 K

$\log (\frac{K_2}{K_1})=\frac{300,000 J/mol}{2.303\times 8.314 J/K mol}[\frac{1}{798.15 K}-\frac{1}{898.15 K}]$

$\log (\frac{K_2}{K_1})=2.185666$

$K_2=153.344\times K_1$

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

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darius12318

22.01.2020

83 mL

Explanation:

Use the dilution equation M1V1 = M2V2

M1 = 18 M

V1 = ?

M2 = 6.0 M

M2 = 250 mL

Solve for V1 --> V1 = M2V2/M1

V1 = (6.0 M)(250 mL) / (18 M) = 83 mL

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