The rusting of iron is represented by the equation 4Fe + 3O2 --> 2Fe2O3. If you have a 3.5-mol sample of iron, how many grams of O2 are needed to rust the iron completely?
34.9 g
84.0 g
16.5 g
48.6 g
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Ответ:
84.0 g
Balanced equation: 4Fe + 3O2 --> 2Fe2O3
3.5-mol sample of ironFind moles of oxygen:
4Fe : 3O24 : 3(3.5/4)*3 = 2.625 molesFind mass of O2
mass = moles * Mrmass = 2.625 * 32mass = 84 gОтвет:
the first one is eubacteria the second one is both the third one is both and the fourth one is archaebacteria
Explanation:
i just did it sorry im late