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HalpMahOnMahH0meW0rk
23.05.2020 •
Chemistry
The specific beta in aluminum is 0,900 J/g • Celsius. How much heat is required to raise the temperature of a 30.0 g block of aluminum from 25 degrees celsius to 75 degrees celsius
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Ответ:
1350J
Explanation:
Heat energy = ?
Mass = 30.0g
Specific heat capacity (c) = 0.90J/g°C
Initial temperature (T1) = 25°C
Final temperature (T2) = 75°C
Heat energy (Q) = mc∇T
Q = heat energy
M = mass of the substance
C = specific heat capacity of the substance
∇T = change in temperature of the substance = T2 - T1
Q = mc∇T
Q = 30 × 0.90 × (75 - 25)
Q = 27 × 50
Q = 1350J
The heat energy required to raise the temperature of the metal from 25°C to 75°C is 1350J
Ответ:
you have 0.340 M which means 0.340 M/1L
you have 150mL which is 0.150L
so if you solve 0.340/1 = x/0.150 math proportion you will get your moles