The speed of a spaceship is going warp 7.58. what is the velocity of the spaceship in cm/min. assume 1.00 warp = 2.5 times the speed of light
speed of light= 2.9979x10^8 m/s

Answer : The velocity of the spaceship is,

Solution :

As we are given that,

The speed of a spaceship = 7.58 wraps

So,

The speed of light =

Now put the value of speed of light in above expression, we get

So,

The velocity of the spaceship =

Now we have to convert the velocity of the spaceship m/s to cm/min.

Conversion :

(1 m = 100 cm)

(1 min = 60 sec)

The velocity of the spaceship =

Therefore, the velocity of the spaceship is,

10 L

Explanation:

The equation of the reaction is;

2BaO2 = 2BaO + O2

Number of moles of  BaO2 = 114.7 g/169.33 g/mol = 0.677 moles

From the reaction equation;

2 moles of BaO2 yields 1 moles of O2

0.677 moles of BaO2 yields 0.677 * 1/2 = 0.3385 moles of oxygen

Hence;

PV=nRT

V = ?

P = 127400 Pa or 1.257 atm

T = 455 K

n = 0.3385 moles

R = 0.082 atmLmol-1K-1

V = nRT/P

V = 0.3385 * 0.082 * 455/1.257

V= 10 L