The temperature of a sample of iron with a mass of 20.0 grams changed from 60.0ºc to 35.0ºc. how many joules of heat were released?
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Ответ:
Assuming c does not change with temperature and has a value of:
c = 0.444 J/K mol, the q can be calculated as:
q = 20.0 g * 0.444 J/K mol * 25 K = 222 J
(Note: K refers to Kelvin which equals ˚C + 273, therefore ΔT is the same in K as it is in ˚C.)
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