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adwinajames
30.10.2019 •
Chemistry
There are 45,000 mg of nitrogen dioxide in a container at stp. what is the volume?
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Ответ:
V = 22.86 L
Explanation:
Given data:
Mass of nitrogen dioxide = 45000 mg
Pressure = 1 atm
Temperature = 273 k
Volume = ?
Solution:
First of all we will convert the mass into moles.
Number of moles = mass/ molar mass
Number of moles = 45 g/ 46 g/mol
Number of moles = 1.02 mol
Now we will determine the volume at STP.
PV = nRT
V = nRT/P
V = 1.02 mol × 0.0821 atm. mol⁻¹. k⁻¹. L× 273 k / 1 atm
V = 22.86 atm. L /1 atm
V = 22.86 L
Ответ:
It is a redox reaction, a combustion reaction.