hardyfombu
01.09.2019 •
Chemistry
Three of the strongest lines in the he+ ion spectrum are observed at the following wavelength:
(1) 11.397 nm
(2) 54.030 nm
(3) 72.941 nm
find the quantum numbers of the initial and final states for the transitions that give rise to these three lines. do this by calculating, the wavelengths of lines that can originate from transitions involving any two of the four lowest levels. when a calculated wavelength matches an observed one, write down n-hi and n-lo for that line. continue until you have assigned all three of the lines.
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Ответ:
(1) e1 = 108.79 ev
(2) e2 = 22.95 ev
(3) e3 = 17.00 ev
since there are no external electric and magnetic fields, then we can ignore stark and zeeman effects respectively. so, we only need to consider the n quantum number.
the energy of an electron in a nucleus of z charge and at nth orbit is given by.
e_n = -13.6*z^2/n^2 ev
let's calculate the energies of the electrons at different energy levels. for helium, z = 2. using the four lowest levels,
e_1 = -54.40 ev
e_2 = -13.60 ev
e_3 = -6.04 ev
e_4 = -3.40 ev
this time we need to calculate the transistion energies for every two pairs of energy levels. there are 4c2 = 6 possible transistion energies.
e_14 = e_4 - e_1 = 51.00 ev
e_13 = e_3 - e_1 = 48.36 ev
e_12 = e_2 - e_1 = 40.80 ev
e_24 = e_4 - e_2 = 10.20 ev
e_23 = e_3 - e_2 = 7.56 ev
e_34 = e_4 - e_3 = 2.64 ev
so it seems that no energy transition matches the change in energy for each jump. so the given wavelengths must be wrong.
Ответ:
1) B. increases
2) B. greater
3) C. Both A and B are correct
4) Activation energy
Explanation:
The rate of a chemical reaction is depend on temperature. If temperature increases, the chemical reaction also increases and vice versa. Fast reaction means which is completely in less time. So atoms in fast reaction have great activation energy and slow reaction have less activation energy. Collision occurs when the particles have energy to move and they collide in proper direction.