Chemistry: To what volume (in milliliters) should you dilute 100.0 ml of a 5.50 m solution of cacl2 solution to obtain a 0.950 m solution of cacl2?

To what volume (in milliliters) should you dilute

kelkel4731

12.03.2022

Dilution law is given as:

$M_{1}V_{1}=M_{2}V_{2}$ (1)

where, $M_{1}$ = molarity of initial concentrated solution.

$V_{1}$ = volume of initial concentrated solution.

$M_{2}$ = molarity of final diluted solution.

tex]V_{2}[/tex] = volume of final diluted solution.

Volume of initial concentrated solution of $CaCl_{2}$ = 100.0 mL

Molarity of initial concentrated solution of $CaCl_{2}$ = 5.50 M

Volume of final diluted solution of $CaCl_{2}$ = 0.950 M

Put the values in formula (1),

$5.50 M\times 100.0 mL=0.950 M\times V_{2}$

$V_{2} =\frac{5.50 M\times 100.0 mL}{0.950 M}$

$V_{2} =578.9 mL$

Hence, final diluted volume of the solution is 578.9 mL .

0,0(0 оценок)

ljwatts25

11.02.2020

Bond type depends on differences in electronegativity.

Metals and nonmetals tend to have large differences in electronegativity.

Nonmetals tend to have smaller differences in electronegativity.

Ionic bonds form between atoms that have large electronegativity differences.

Covalent bonds form between atoms with small electronegativity differences.

0,0(0 оценок)