Trimethylamine, (CH3)2N is a weak base (K6 = 6.3 x 10-5). What volume of this gas, measured at STP, must be dissolved in 2.5 L of solution to give that solution a pOH of 2.50? PLEASE HELP ITS DUE IN 20 mins :

The volume of the gas = 9.133 L

Further explanation

Given

Kb = 6.3 x 10⁻⁵

2.5 L solution

pOH= 2.5

Required

Volume of gas

Solution

pOH = 2.5

For weak base :

mol = M x V

mol = 0.163 x 2.5 L

mol = 0.408

Use ideal gas law at STP(1 atm, 273 K) :

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hope I could help!