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trejo282961
03.07.2019 •
Chemistry
Two solutions, initially at 24.60°c, are mixed in a coffee cup calorimeter (ccal = 15.5 j/°c). when a 100.0 ml volume of 0.100 m agno3 solution is mixed with a 100.0 ml sample of 0.200 m nacl solution, the temperature in the calorimeter rises to 25.30°c. determine the dh°rxn for the reaction as written below. assume that the density and heat capacity of the solutions is the same as that of water. nacl(aq) + agno3(aq) → agcl(s) + nano3(aq) dh°rxn = ?
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Ответ:
Hey there!:
moles of AgNO3 = 100 x 0.1 / 1000 = 0.01
moles of NaCl = 100 x 0.200 / 1000 = 0.02
volume of solution = 100 + 100 = 200 mL
mass of solution = 200 x 1 = 200 g
temperature rise = 25.30 - 24.60 = 0.70ºC
Therefore:
Q = m* Cp* ΔT + Cp* ΔT =
200* 4.184 * 0.70 + 15.5 * 0.70 =
Q = 596.61 J
Given the reaction:
Q = 596.61 J
NaCl(aq) + AgNO3(aq)> AgCl(s) + NaNO3(aq)
1 mole NaCl 1 mole AgNO3 1 mole AgCl
0.02 moles NaCl 0.01 moles AgNO3
So:
ΔH = - Q / T
ΔH = - 596.61 * 10⁻³ / 0.01
ΔH = - 59.66 kJ
Hope that helps!
Ответ:
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