Two water molecules are separated by 2.76 Å in air. Use equation 13.9 to calculate the dipole-dipole interaction (in kJ/mol). The dipole moment of water is 1.82 D. Hint: eq. 13.9:VV

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Ответ:

kieramacphee3946

08.06.2020

Chemistry

$1.67 \times 10^{-12}$ picograms

Explanation:

Mass of a proton = $1.67 \times 10^{-27}$ kilograms

Since 1 kilo = 1000 = 10³, we can write:

Mass of a proton = $1.67 \times 10^{-27} \times 10^{3}$ grams = $1.67 \times 10^{-24}$ grams

We need to convert the mass of proton to picograms

Remember that pic stands for $10^{-12}$

So, 1 picogram = $10^{-12}$ gram

We can re-write the mass of proton as:

$1.67 \times 10^{-24} \times 10^{12} \times 10^{-12} \text{ gram}\\\\= 1.67 \times 10^{-24+12} \text{ picogram}\\\\= 1.67 \times 10^{-12} \text{ picogram}$

Thus,

Mass on proton in is $1.67 \times 10^{-12}$ picograms

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