Use boyle's law to explain what would happen to the volume of a helium- filled balloon if it was carried underwater by a diver to increasing depths and higher pressure. assume that the temperature of the gas remains constant.

The deeper the diver takes the helium balloon, the more it reduces in size. This is due to the pressure of the water column above pressing on the balloon. According to Boyle’s law (P= k*1/V.), as the volume of the balloon decreases, the pressure of the helium inside increases.

If we are Solving for X, then the answer would be, 0.

Step-by-step explanation: Both of the X's cancel each other out which then makes it 5 - 5 = 0, or, 0 = 5 - 5.

I hope this helped!