Use the balanced equation below to answer the question that follows 6 CO2 + 6 H20 -> C6H12O6 +6O2
How many moles of water are needed to produce 4 moles of C6H12O6?
a. 4
b. 6
c. 10
d. 24

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Ответ:

dnicole43

25.09.2022

Chemistry

The answer to the question is

It will be ≅ 28.8 years until only 35 % of the substance remains

Explanation:

To solve this we note the required relations and the given variables thus

The half life of the substance is

N(t) = N(0) × $(\frac{1}{2} )^{\frac{t}{t_{\frac{1}{2} } } }$

Thus when only 35% is remaining we have

35% of N(0) = N(0)× $(\frac{1}{2} )^{\frac{t}{t_{\frac{1}{2} } } }$

or 0.35 = $(\frac{1}{2} )^{\frac{t}{t_{\frac{1}{2} } } }$ , to solve the previous equation, we take the log of both sides thus

Log (0.35) = Log ( $(\frac{1}{2} )^{\frac{t}{t_{\frac{1}{2} } } }$ ) or $\frac{t}{t_{\frac{1}{2} } }$ × log (1/2) =log(0.35)

⇒ $\frac{t}{t_{\frac{1}{2} } }$ = 1.515 and since $t_{\frac{1}{2} }$ = 19 years we have

t = 19 × 1.515 = 28.776 Years

Therefore it will be 28.776 years before 35 % of the substance will be remaining

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Use the balanced equation below to answer the question that follows 6 CO2 + 6 H20 -> C6H12O6 +6O2 How many moles of water are needed to produce 4 moles of C6H12O6? a. 4 b. 6 c. 10 d. 24