screamqueen
18.04.2020 •
Chemistry
Use the following data to calculate the standard enthalpy of formation of pentane, C5H12(l)?
C5H12(l) + 8 O2 (g) -> 5 CO2 (g) + 6 H2O (l) delta H=-3535.9 kJ/mol
delta Hf of CO2 (g) = -393.5 kJ/mol
delta Hf of H2O (l) = -285.8 kJ/mol
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Ответ:
Explanation:
C₅H₁₂(l) + 8O₂(g) ⟶ 5CO₂(g) + 6H₂O(l); ΔᵣH = -3535.9 kJ·mol⁻¹
The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is
Let x = the heat of formation of pentane
C₅H₁₂(l) + 8O₂(g) ⟶ 5CO₂(g) + 6H₂O(l)
ΔH°f/kJ·mol⁻¹: x -393.5 -285.8
Ответ:
-57.12
Explanation:
i used a calculator :)