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BWomack214
06.12.2019 •
Chemistry
Use the standard free energies of formation (δgf°) of each substance to determine the value of equilibrium constant k at 25 °c for the following reaction. click here for a copy of the test 3 cover sheet.
co2(g) + 2 h2(g) ⇌ ch3oh(l)
δgf° kj/mol −394.4 0 −166.4
0
0.91
8.83 × 1039
1.13 × 10−40
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Ответ:
k = 8,83x10³⁹
Explanation:
For the reaction:
CO₂(g) + 2H₂(g) ⇌ CH₃OH(l)
ΔG° = ΔGproducts - ΔGreactants
ΔG° = ΔGCH₃OH(l) - (ΔGCO₂(g) + 2ΔGH₂(g)
As ΔGCH₃OH(l) = -166,4 kJ/mol; ΔGCO₂(g) = -394,4 kJ/mol; ΔGH₂(g) = 0 kJ/mol
ΔG° = -166,4 kJ/mol - (-394,4 kJ/mol + 2×0 kJ/mol)
ΔG° = 228,0 kJ/mol
The ΔG could be defined as:
ΔG = -RT lnK
Where R is gas constant (8,314472x10⁻³ kJ/molK); Temperature is 25°C, 298,15K.
Replacing:
228,0 kJ/mol = 8,314472x10⁻³ kJ/molK×298,15K ln K
91,97 = ln k
K = 8,79x10³⁹ ≈ 8,83x10³⁹
I hope it helps!
Ответ: