Chemistry: Water enters a 4.00-m3 tank at a rate of 6.33 kg/s and is withdrawn at a rate of 3.25 kg/s. the tank is initially half full. what is the volume of the tank not occupied by water at the start of the process?

Water enters a 4.00-m3 tank at a rate of 6.33 kg/s

tcarston1728

03.01.2022

At the start of the process, the volume not occupied by the water is 2 m3

Explanation:

At the start of the process you have a half full tank. It means that also a half is empty (not occupied by water).

Since the volume is 4 m3, 2 m3 are full (occupied by water) and 2 m3 (not occupied by water).

The volume in time will be

$V(t)=V_0+(f_i-f_o)*t\\\\V(t) = 2 +(6.33/1000-3.25/1000)*t=2+0.00308*t \, \, [m3]$

0,0(0 оценок)

moongirl4791

18.08.2020

2 atoms

Explanation:

0,0(0 оценок)