Water has a heat of fusion of about 300J/gram and a heat capacity for liquid water of a about 4J/gC. How much heat is needed to warm a 10 gram block of solid ice at 0 degree celcius to 10 degree celcius?
A. 30.4 KJ
B. 3.4 KJ
C. 0.3 KJ
D. 3.04 KJ
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Ответ:
The total heat required is 3.4 kJ
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
There is a direct proportional relationship between heat and temperature. So, the amount of heat a body receives or transmits is determined by:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case you know;
Q= ?c= 4 m= 10 gΔT= Tfinal - Tinitial= 10 C - 0 C= 10 CReplacing:
Solving:
Q1= 400 J
On the other hand, you must determine the heat required to convert 0 ∘ C of ice to 0 ∘ C of liquid water by:
Q2=m*heat of fusion
Q2=10 g* 300
Q2= 3,000 J
The total heat required is:
Q= Q1 + Q2= 400 J + 3,000 J
Q= 3,400 J= 3.4 kJ (1 kJ= 1,000 J)
The total heat required is 3.4 kJ
Ответ:
87 ÷ 0.45
= 193.333… lbs
i don’t know how many significant figures you have to do but if it’s 3 significant figures then the answer is 193lbs
lbs = pounds