Chemistry: Wenzhou prepares 200 ml of a solution of sncl4in which the concentration ofchloride ions is 0.240m.a) what is the molarity of the sncl4solution (i.e. what should the bottle be labeled)? b) what mass of sncl4did wenzhou use?

Could you please send a picture of the data? Other wise I cannot tell....

Wenzhou prepares 200 ml of a solution of sncl4in

JaredO

05.01.2022

a) 0.06 M

b) 3.13 grams.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{moles}{\text {Volume in L}}$

Moles of $Cl^-=Molarity\times {\text {Volume in L}}=0.240\times 0.2L=0.048moles$

The balanced reaction for dissociation will be:

$SnCl_4\rightarrow Sn^{4+}+4Cl^{-}$

Thus for 4 moles of Cl^- , there is 1 mole of SnCl_4

Thus moles of $SnCl_4=\frac{1}{4}\times 0.048=0.012$

Molarity of $SnCl_4=\frac{moles}{\text {Volume in L}}=\frac{0.012}{0.2L}=0.06M$

Thus the molarity of the SnCl_4 solution = 0.06 M

b) Mass of SnCl_4 = $moles\times {\text {Molar mass}}=0.012mol\times 260.522g/mol=3.13g$

Thus mass of SnCl_4 Wenzhou use is 3.13 grams.

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