What are [H3O+], [OH?], and pH in a solution with a pOH of 11.17? Make sure your answers are given to the correct number of significant figures. [H3O+] = __ x 10 __ M
[OH?] = __ x 10 __ M
pH= __

[OH⁻]= 6.76*10⁻¹² M

pH= 2.83

[H₃O⁺]= 1.48*10⁻³

Explanation:

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution that indicates the concentration of hydroxyl ions [OH-] present in a solution. The pOH is defined as the logarithm of the concentration of OH- ions, with the sign changed:

pOH= -log[OH⁻]

In this case, pOH= 11.17. So:

11.17= -log [OH⁻]

Solving:

-11.17=log [OH⁻]

10⁻¹¹ ¹⁷= [OH⁻]

6.76*10⁻¹² M= [OH⁻]

pH, short for hydrogen potential, is a parameter that indicates the concentration of hydrogen ions [H⁺] or [H₃O⁺] that exist in a solution and is calculated as the logarithm of the concentration of H⁺ ions, with the sign changed:

pH= -log[H⁺]= -log[H₃O⁺]

The relationship between pH and pOH can be established by the expression:

pH + pOH= 14

In this case, being pOH=11.17:

pH + 11.17= 14

and solving you get:

pH= 14 - 11.17

pH= 2.83

Finally,  replacing this value in the definition of pH:

2.83= -log [H₃O⁺]

and solving you get:

-2.83= log [H₃O⁺]

10⁻² ⁸³= [H₃O⁺]

1.48*10⁻³=  [H₃O⁺]

Italy was ready to fight but got scared.

Explanation:

On July 25, the day after Mussolini’s arrest, the first Italian troops began withdrawing from Sicily. Hitler instructed his forces to make contingency plans for withdrawal but to continue to fight fiercely against the Allied advance. As July turned to August, Patton and Montgomery and their armies battled against determined German troops dug into the mountainous Sicilian terrain. The U.S. and British soldiers pushed back the Axis forces farther and farther until most were trapped in a northeast corner of the island.