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taminazaka1
14.07.2019 •
Chemistry
What electron has the electron configuration 1s22s22p63s23p2?
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Ответ:
Ответ:
Thus percentage purity of sodium carbonate is 60.83%.
Explanation:
Volume of the HCl solution ,V = 15.55 mL= 0.01555 L
Concentration of HCl solution ,C= 0.1755 M
Moles of HCl in 0.1755 M solution = n
According o reaction 2 moles of HCl reacts with 1 mole of sodium carbonate.
Then n moles of HCl will react with:
Mass of
of sodium carbonate:
Mass of the sample given= 0.2377 grams
Mass used up in reaction = 0.144585 g
percentage purity=![\frac{0.144585}{0.2337}\times 100=60.83\%](/tpl/images/0225/9404/6c685.png)
Thus percentage purity of sodium carbonate is 60.83%.