What is its molar heat of vaporization in kilojoules per mole if its vapor pressure at 20°C is 11.0 torr?

H.vap = 6.544 kJ/mol

Explanation:

Clausius-Clapeyron Equation

In P = H.vap / RT where T = 20 + 273 = 293K

H.vap = In P (RT) = In 11 (8.314 x 293) = 6543.861 J/mol = 6.544 kJ/mol

34 Grams

Source :

https://socratic.org/questions/what-is-the-maximum-amount-of-kci-that-can-dissolve-in-300-g-of-water-at-20-c#:~:text=This%20means%20that%20at%2020,every%20100%20g%20of%20water.