Chemistry: What is Ką for H3BO3(aq) = H+(aq) + H2B03 (aq)?

What is Ką for H3BO3(aq) = H+(aq) + H2B03 (aq)?

chrjergre6520

29.01.2022

Answer : The expression for acid dissociation constant will be:

$K_a=\frac{[H^+][H_2BO_3^-]}{[H_3BO_3]}$

Explanation :

Acid dissociation constant : It is an equilibrium constant that refers to the dissociation or ionization of an acid.

It is denoted as K_a .

The given equilibrium reaction is:

$H_3BO_3(aq)\rightleftharpoons H^+(aq)+H_2BO_3^-(aq)$

The expression for acid dissociation constant will be:

$K_a=\frac{[H^+][H_2BO_3^-]}{[H_3BO_3]}$

0,0(0 оценок)

dondre54

10.12.2020

The answer is

0.075 kg

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question

density = 762 kg/m³

We must first convert the volume from cm³ to m³

$1 \: {cm}^{3} = 1 \times {10}^{ - 6} {m}^{3}$

So 99 cm³ will be

$9.9 \times {10 }^{ - 5} \: \: {m}^{3}$

So the mass of the material is

$mass = 762 \times 9.9 \times {10}^{ - 5} \\ = 0.075438$

We have the final answer as

0.075 kg

Hope this helps you

0,0(0 оценок)