What is the acceleration of a 9.6-kg rock if gravity pulls it downward, but air resistance pushes upward with a force of 2.8 n?

OK, so the downward force on the rock is mg (force of g) - 2.8N (force in opposite direction). since mg (9.6 kg*9.8 m/s^2)= 94.08 N, then mg-2.8= 91.28 N. That is your net force on the rock (or total force). And, since f=ma, a= f/m.
so, a= 91.28 N / 9.6 kg = 9.5 m/s^2.(final answer)

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