Chemistry: What is the boiling point of a solution of 9.04 g of i2 in 75.5 g of benzene, assuming the i2 is nonvolatile?

What is the boiling point of a solution of 9.04

Ответ:

nahimi

16.03.2022

Chemistry

374.2 K

Explanation:- Elevation in boiling point is:

$\Delta T_b=k_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

T_f = change in boiling point

k_b = boiling point constant= 2.53Kkg/mol

m = molality

Given: mass of solute (I_2) = 9.04 g

Molar mass of solute (I_2) = 254 g/mol

Weight of solvent (benzene)= 75.5 g= 0.0755 kg

$\Delta T_b=2.53 Kkg/mol\times \frac{9.04g}{254g/mol\times 0.0755kg}=1.2K$

$\Delta T_b=1.2 K=T_b-T^0_b=T_b-373K$

T_b=374.2K

The boiling point of the solution is 374.2K .

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Ответ:

deadpoolcorvettehats

04.03.2022

Chemistry

A covalent bond describes two atoms (most likely nonmetals) that share their valence electrons to satisfy the octet rule. Carbon and oxygen are both nonmetals, and they would share electrons with each other through a bond that is not polar enough to be considered ionic. The answer should be B

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What is the boiling point of a solution of 9.04 g of i2 in 75.5 g of benzene, assuming the i2 is nonvolatile?

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