Chemistry: What is the change in enthalpy in kilojoules when 3.24 g of CH3OH is completely reacted according to the following reaction 2 CH3OH -- 4 CH4 + O2 ∆H =252.8 Kj

What is the change in enthalpy in kilojoules when

Ответ:

umezinwachukwuebuka1

05.02.2022

Chemistry

12.78 kJ

Explanation:

The correct balanced reaction would be

$2CH_3OH\rightarrow 2CH_4+O_2\Delta H=252.8\ \text{kJ}$

Mass of methanol = $3.24\ \text{g}$

Moles of methanol can be obtained by dividing the mass of methanol with its molar mass $(32.04\ \text{g/mol})$

$\dfrac{3.24}{32.04}=0.10112\ \text{moles}$

Enthalpy change for the number of moles is given by

$\dfrac{\text{Number of moles of methanol in the reaction}}{\text{Enthalpy change in the reaction}}=\dfrac{\text{Number of moles in 3.24 g of methanol}}{\text{Enthaply in change in the mass of methanol}}$

$\\\Rightarrow\dfrac{2}{252.8}=\dfrac{0.10112}{\Delta H}\\\Rightarrow \Delta H=\dfrac{0.10112\times 252.8}{2}\\\Rightarrow \Delta H=12.781568\approx 12.78\ \text{kJ}$

The change in enthalpy is 12.78 kJ.

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Ответ:

jaeybird9

27.06.2022

Chemistry

This law states that, despite chemical reactions or physical transformations,
mass is conserved, that is, it cannot be created or destroyed. within an isolated system. In other words, in a chemical reaction, the mass of the products will always be equal to the mass of the reactants.

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What is the change in enthalpy in kilojoules when 3.24 g of CH3OH is completely reacted according to the following reaction 2 CH3OH -->4 CH4 + O2 ∆H =252.8 Kj

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