What is the concentration (M) of HCl if 0.05 mL (1 drop!) can neutralize 1.5 mL of 0.2 M NaOH? I
What is the concentration of NaOH (M) if 1,050.0 mL can be neutralized by 17.5 mL of 3 M HCI?

Solved

Show answers

Ответ:

hdhdhd49jdhd

18.01.2022

Chemistry

It will take 6.6 hours for 75% of the lead to decay.

Explanation:

The radioactive decay follows first order rate law

The half life and rate constant are related as

$k=rate constant=\frac{0.693}{halflife}=\frac{0.693}{3.3}=0.21h^{-1}$

The rate law for first order reaction is

$time=\frac{1}{k}(ln[\frac{A_{0}}{A_{t}}]$

Where

A0 = initial concentration = 1 g

At= final concentration = 0.25 g (as 75% undergoes decay so 25% left]

$time=\frac{1}{0.21}(ln(\frac{1}{0.25})=6.6hours$

0,0(0 оценок)

Ask your question to the AI advisor

Ai-bot is an expert in any field and is the perfect companion for reliable and useful answers and advice on a variety of topics, including science, history, technology, art, sports, health, culture and more.

Ask your question

More tips

Answers on questions: Chemistry

Ask an AI advisor a question

I want advice

What is the concentration (M) of HCl if 0.05 mL (1 drop!) can neutralize 1.5 mL of 0.2 M NaOH? I What is the concentration of NaOH (M) if 1,050.0 mL can be neutralized by 17.5 mL of 3 M HCI?