What is the final concentration, in mg/mL, for a solution prepared by adding 12.00 mL of a 3.590 mg/mL Cu2+ stock solution into 100.00 mL volumetric flask and filled with water to the calibration mark?

0.4308 mg/mL

Explanation:

Given data

We can find the final concentration using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 3.590 mg/mL × 12.00 mL / 100.00 mL

C₂ = 0.4308 mg/mL

             48.13 mL

Solution:

Data Given:

                  Mass  =  1.03 Kg  =  1030 g

                  Density  =  21.4 g/cm³

To Find:

                  Volume  =  ?

Formula Used:

                       Density  =  Mass  ÷  Volume

Solving for Volume,

                       Volume  =  Mass  ÷  Density

Putting Values,

                       Volume  =  1030 g  ÷  21.4 g.cm⁻³

                       Volume  =  48.13 cm³

As,

                       1 cm³  =  1 mL

So,

                       48.13 cm³  =  48.13 mL