Chemistry: What is the formula mass of MgO (how much does one mole of it weigh)

What is the formula mass of MgO (how much does one

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alondrahernande3

08.12.2020

Chemistry

- 27.7 grams of PbI_2 are produced.

Solution:- The balanced equation is:

$Pb(NO_3)_2+2NaI\rightarrow PbI_2+2NaNO_3$

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of Pb(NO_3)_2 = 207.2+2(14.01)+6(16) = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2 = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

$28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})$

= 39.0gPbI_2

$18.0gNaI(\frac{1molNaI}{149.89gNaI})(\frac{1molPbI_2}{2molNaI})(\frac{461gPbI_2}{1molPbI_2})$

= 27.7gPbI_2

From above calculations, NaI gives least amount of PbI_2 , so the answer is, 27.7 g of PbI_2 are produced.

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What is the formula mass of MgO (how much does one mole of it weigh)

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