What is the mass of 2.56 × 10–4 moles of fe2o3? : 6.23 × 105 159.6 g 1.60 × 0–6 g 4.09 × 10–2 g
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Ответ:
4.09 × 10⁻² g
Solution:
As we know that,
1 mol of Fe₂O₃ is equal to = 159.69 g
So,
2.56 × 10⁻⁴ mol will be equal to = X g
Solving for X,
X = (159.69 g × 2.56 × 10⁻⁴ mol) ÷ 1 mol
X = 0.04088 g
Or,
X = 0.049 g
Or,
X = 4.09 × 10⁻² g
Ответ:
the answer is 1.75 i just took the test