What is the mass of 6.728 x 10^23 atoms Ag?

18.02 g

Explanation:

im pretty sure thats the anwser but im not 100% sure if it correct

1.21*10^2 g

Explanation:

6.728*10^23 atom Ag *1 mol/6.022*10^23 (Avogadro's number)*107.868 g (Ag atomic mass)/1 mol = 120.514099 g > (rounded and scientific notation)  1.21*10^2 g

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